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6x^2-14x=2x-8
We move all terms to the left:
6x^2-14x-(2x-8)=0
We get rid of parentheses
6x^2-14x-2x+8=0
We add all the numbers together, and all the variables
6x^2-16x+8=0
a = 6; b = -16; c = +8;
Δ = b2-4ac
Δ = -162-4·6·8
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8}{2*6}=\frac{8}{12} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8}{2*6}=\frac{24}{12} =2 $
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